trial4.py

L1 = [1, 'b', 1, 'c', 'c', 1]
L2 = ['c', 1, 'b', 1, 1, 'c']


def isPermutation(list1,list2):
 if len(list1) != len(list2):
   return False;  #two list does not have same length so impossible being permutation of each other
 for i in range(0, len(list1)):
   if list1.count(list1[i]) != list2.count(list1[i]):
     return False

def is_list_permutation(list1,list2):
  if (isPermutation(list1,list2) == False): #use the above method isPermutation to check if they are permutation of each other
    return False #if not return false
  elif not list1:
    return (None, None, None)
  else:
    mostOccurItem = max(set(list1), key=list1.count)  
    numberOfTimes = list1.count(mostOccurItem)
    theType = type(mostOccurItem)
    return (mostOccurItem, numberOfTimes, theType)

print(is_list_permutation(L1,L2))