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Copy path1209. Remove All Adjacent Duplicates in String II.cpp
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1209. Remove All Adjacent Duplicates in String II.cpp
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#include<iostream>
#include<stack>
using namespace std;
// You are given a string s and an integer k, a k duplicate removal consists of choosing k adjacent and equal letters from s and removing them, causing the left and the right side of the deleted substring to concatenate together.
// We repeatedly make k duplicate removals on s until we no longer can.
// Return the final string after all such duplicate removals have been made. It is guaranteed that the answer is unique.
// Example 1:
// Input: s = "abcd", k = 2
// Output: "abcd"
// Explanation: There's nothing to delete.
// Example 2:
// Input: s = "deeedbbcccbdaa", k = 3
// Output: "aa"
// Explanation:
// First delete "eee" and "ccc", get "ddbbbdaa"
// Then delete "bbb", get "dddaa"
// Finally delete "ddd", get "aa"
// Example 3:
// Input: s = "pbbcggttciiippooaais", k = 2
// Output: "ps"
// Constraints:
// 1 <= s.length <= 105
// 2 <= k <= 104
// s only contains lower case English letters.
class Solution {
public:
string removeDuplicates(string s, int k) {
if(s.length() == 0){
return s;
}
for(int i=0;i<s.length();i++){
if(stack.empty() == false && stack.top().first == s[i]){
stack.top().second++;
if(stack.top().second==k){
stack.pop();
}
}
else{
stack.push({s[i],1});
}
}
string answer;
while(stack.empty()==false){
while(stack.top().second != 0){
answer.push_back(stack.top().first);
stack.top().second -= 1;
}
stack.pop();
}
reverse(answer.begin(),answer.end());
return answer;
}
private:
stack<pair<char,int>> stack;
};
int main(){
Solution solution;
string input = "deeedbbcccbdaa";
cout << input << endl;
string answer = solution.removeDuplicates(input,3);
cout << answer << endl;
}