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Where to put the sign when solving absolute value problems #547
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I think I agree! @AbbyANoble @tdegeorge @kathypinzon , I don't remember which one of y'all wrote this, but what do y'all think? |
I don't remember who wrote this one (though it's not looking familiar so I don't think it was me?), but I prefer it the way it is because it models the words I would use to describe what's going on when you solve. So for like the beginning of all this we might look at Regarding the inequalities, I still prefer it as it is to emphasize the potential locations after you travel a certain distance on the number line. For |
For what it's worth, I didn't do this section last semester so I haven't looked super closely. But if I did do it in the future, I would use my own notes if we made this change. |
It seems to me there are two viewpoints here: one I would call definition and the other I would call meaning. Honestly, I'm not even sure I have those labels correct. In any case, I think both provide useful insight. The definition idea I suggested provides a mechanical way of ensuring that the sign is handled reliably, while using the meaning of distance from zero provides a way of reasoning to the answer. Having both ideas in mind can actually help one check their answer. |
Maybe the trouble I am trying to avoid with my suggestion is the student who gets caught between the two ideas and applies the plus and minus signs to the right hand side of the inequality without the reasoning part, resulting in However the text ends up, I would still present both viewpoints. My original comment was only meant to say that Remark 1.4.1 seems immediately de-emphasized in favor of the view introduced in the first sentence of Activity 1.4.3. If the intent is to emphasize that perspective, perhaps that sentence should be given its own remark. |
This might need some discussion.
Remark 1.4.4 Remark 1.4.4$|ax+b| = c$ as $ax+b = c$ and $ax+b = -c$ .
https://tbil.org/preview/precalculus/EQ4.html#EQ4-3-5 suggests rewriting
I think it would make better sense to write it as$ax+b = c$ and $-(ax+b)=c$ .
Rationale:
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