Incorrect_keyboard.c

/*Incorrect keyboard

Suman's keyboard got damaged as he dropped it from a considerable distance. As a result instead of K the keyboard may sometimes display T (but will never display K instead of T)
Similarly instead of G, the keyboard may sometimes display D, instead of R sometimes it may display L and sometimes instead of R it displays F.

Because of this Suman has to think of all possible words for a displayed word (obtained by typing using his keyboard). The program to be written should accept a word W which is displayed as a result of typing on Suman's keyboard and should calculate how many possible words it could mean (if typed using a properly working keyboard) and print the count as the output.

Boundary Conditions:
The length of the input word is between 2 and 100.

Input Format:
First line will contain the word W.

Output Format:
The count of possible words that the input word (typed using Suman's keyboard) could mean.


Sample Input/Output:

Example 1:

Input:
FILIPEK

Output:
4

Explanation:
The words that may be wrongly typed are F and L. Here F could be correctly typed or wrongly typed instead of R. Similarly L could be correctly typed or wrongly typed instead of R.
Hence the overall words to be considered are 2*2 = 4.
Note: K is not considered as K will not be typed instead of some other letter. Only instead of K sometimes T will be typed.


Example 2:
Input:
KICKED

Output:
2

Explanation:
D could be correctly typed or wrongly typed instead of G. Hence overall words to be considered = 2.


Example 3:
Input:
FUTILE

Output:
8

Explanation:
F,T,L - These three letters can be wrongly typed instead of R,K,R or can be correctly typed. Hence overall words to be considered = 2*2*2 = 8.
*/

#include<stdio.h>
#include<string.h>
int main(){
	char str[200];
	scanf("%s",str);
	int len=strlen(str),i,p=1;;
	for(i=0;i<len;i++){
		if(str[i]=='F' || str[i]=='L' || str[i]=='D' || str[i]=='G' || str[i]=='T')
			p*=2;
	}
	printf("%d",p);
	return 0;
}