D-1submission.md

👺 Question-Largest Time for Given Digits

Given an array of 4 digits, return the largest 24 hour time that can be made.
The smallest 24 hour time is 00:00, and the largest is 23:59. Starting from 00:00, a time is larger if more time has elapsed since midnight.
Return the answer as a string of length 5. If no valid time can be made, return an empty string.
Example 1:
nput: [1,2,3,4]
Output: "23:41"
Example 2:
Input: [5,5,5,5]
Output: ""
Note:
A.length == 4
0 <= A[i] <= 9

🍱 Solution

class Solution {
    public String largestTimeFromDigits(int[] arr) {
        int i,j,k,l;
        String res="",hr,time,min;
        for(i=0;i<4;i++){
            for(j=0;j<4;j++){
                for(k=0;k<4;k++){
                    if(i==j || j==k || k==i){
                        continue;
                    }
                    hr=""+arr[i]+arr[j];
                    min=""+arr[k]+arr[6-i-j-k];
                    time=hr+":"+min;
                    if(hr.compareTo("24")<0 && min.compareTo("60")<0 && res.compareTo(time)<0){
                        res=time;
                    }
                }
            }
        }
          return res;
    }
  
}