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AOJ2534.cpp
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#include <bits/stdc++.h>
using namespace std;
using VS = vector<string>; using LL = long long;
using VI = vector<int>; using VVI = vector<VI>;
using PII = pair<int, int>; using PLL = pair<LL, LL>;
using VL = vector<LL>; using VVL = vector<VL>;
#define ALL(a) begin((a)),end((a))
#define RALL(a) (a).rbegin(), (a).rend()
#define SZ(a) int((a).size())
#define SORT(c) sort(ALL((c)))
#define RSORT(c) sort(RALL((c)))
#define UNIQ(c) (c).erase(unique(ALL((c))), end((c)))
#define FOR(i, s, e) for (int(i) = (s); (i) < (e); (i)++)
#define FORR(i, s, e) for (int(i) = (s); (i) > (e); (i)--)
//#pragma GCC optimize ("-O3")
#ifdef YANG33
#include "mydebug.hpp"
#else
#define DD(x)
#endif
const int INF = 1e9; const LL LINF = 1e16;
const LL MOD = 1000000007; const double PI = acos(-1.0);
/* ----- 2019/05/26 Problem: AOJ 2534 / Link: https://onlinejudge.u-aizu.ac.jp/challenges/search/volumes/2534 ----- */
template<typename T>
vector<T> topological_sort(const vector<vector<T>> &g) {
int n = (int)g.size(), k = 0;
vector<T> ord(n, 0), in(n, 0);
for (int i = 0; i < (int)g.size(); i++)
for (int j = 0; j < (int)g[i].size(); j++)
in[g[i][j]]++;//入次数
queue<T> q;
for (int i = 0; i < n; ++i)
if (in[i] == 0) q.push(i);//0なら先頭
while (q.size()) {
int v = q.front(); q.pop();
ord[k++] = v;//番号付けと緩和
for (int i = 0; i < (int)g[v].size(); i++)
if (--in[g[v][i]] == 0) q.push(g[v][i]);
}
return *max_element(in.begin(), in.end()) == 0 ? ord : vector<T>();
}
int main() {
cin.tie(0);
ios_base::sync_with_stdio(false);
// isdag?
int N;
while (cin >> N, N) {
// n:500, s:10
// prefixが同じやつの次に対して定義
// 隣だけみても問題ない
VS a(N);
FOR(i, 0, N) {
cin >> a[i];
}
bool ok = 1;
VVI G(26);// s<t : s->t
FOR(i, 0, N - 1) {
string s = a[i];
string t = a[i + 1];
DD(de(s, t));
bool diff = 0;
FOR(x, 0, min(SZ(s), SZ(t))) {
if (s[x] == t[x])continue;
else {
diff = 1;
s[x] -= 'a';
t[x] -= 'a';
G[s[x]].push_back(t[x]);
DD(de(int(s[x]), "->", int(t[x])));
break;
}
}
if (!diff && (SZ(s) > SZ(t))) {
ok = 0;
}
}
DD(de(ok));
ok &= topological_sort(G) != VI();
auto print_yesno = [](LL yes, int mode = 0) {
if (mode == 0) {
cout << (yes ? "yes" : "no") << endl;
}
else if (mode == 1) {
cout << (yes ? "Yes" : "No") << endl;
}
else if (mode == 2) {
cout << (yes ? "YES" : "NO") << endl;
}
else assert(0);
};
print_yesno(ok, 0);
}
return 0;
}