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AdjustDigits.cs
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using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace AdjustDigits
{
class Program
{
static void Main(string[] args)
{
//目标为控制位数在10位
string Number;
Console.WriteLine("请输入数字");
Number = Console.ReadLine();
Number = Number.Trim();
int CountDecimalPoint = 0;
int ScientificNumber;
string ScientificNotation = "";
int digits_part;
BigNumber NumberProcess = new BigNumber("0");
string ProcessedNumber;
char[] separator = { '.' };
//用于分割小数点
string[] NumberParts = new string[2];
int IsNegative = 0;
//用来判定数字是否为负
int zero_count = 0;
//用于计算小数点后有多少个零
NumberParts = Number.Split(separator);
if (NumberParts[0].Length + 5 > 10)
//四位小数加上1个小数点
{
if (Number[0] == '-'){
IsNegative = 1;
}
foreach (char FindDecimalPoint in Number)
{
if (FindDecimalPoint == '.')
{
CountDecimalPoint = 1;
break;
}
}
if (CountDecimalPoint == 0)
{
//无小数点则只有整数部分
ScientificNumber = Number.Length - IsNegative - 1;
//转换为科学计数法
//Console.WriteLine("ScientificNumber = {0}", ScientificNumber);
if (ScientificNumber <= 9 && ScientificNumber > 0)
{
ScientificNotation = "0" + ScientificNumber.ToString();
//如果科学计数法为个位要补零
}
else
{
ScientificNotation = ScientificNumber.ToString();
}
//数字正负无需考虑
if (ScientificNotation.Length + 1 + 2 <= 9)
{
//例如：-3.1415E+05
//数字负号占一位，E和科学计数法的符号占两位
//大于9的情况不做考虑，数字太大。
digits_part = 9 - (ScientificNotation.Length + 1 + 2);
//小数位由此算出
NumberProcess = new BigNumber (Number.ToString()) / (new BigNumber("10")).Power(new BigNumber(ScientificNumber.ToString()),30);
//Console.WriteLine("ScientificNotation = {0},digits_part = {1},NumberProcess = {2}", ScientificNotation, digits_part, NumberProcess.ToString());
ProcessedNumber = MathV.round(NumberProcess.ToString(), digits_part, 0) + "E+"+ScientificNotation ;
//Console.WriteLine("ProcessedNumber ={0}", ProcessedNumber);
}
else
{
//如果已经大于已经大于九位了，则不作处理
//这种情况极为罕见，不考虑
NumberProcess = new BigNumber(Number.ToString()) / (new BigNumber("10")).Power(new BigNumber(ScientificNumber.ToString()), 30);
ProcessedNumber = MathV.round(NumberProcess.ToString(), 0, 0) + "E+" + ScientificNotation;
}
}
else
{
//有小数点的情况
NumberParts = Number.Split(separator);
if (NumberParts[0] != "0")
{
if (NumberParts[0].Length + 1 + 4 >= 9)
{
//如果保留四位小数之后依旧总长度超过九，则进行如下操作
//判断整数部分是否为0
//如果不为0，继续科学计数法的处理，舍去小数部分
ScientificNumber = NumberParts[0].Length - IsNegative - 1;
//转换为科学计数法
if (ScientificNumber <= 9 && ScientificNumber > 0)
{
ScientificNotation = "0" + ScientificNumber.ToString();
//如果科学计数法为个位要补零
}
else
{
ScientificNotation = ScientificNumber.ToString();
}
//数字正负无需考虑
if (ScientificNotation.Length + 1 + 2 <= 9)
{
//例如：-3.1415E+05
//数字负号占一位，E和科学计数法的符号占两位
//大于9的情况不做考虑，数字太大。
digits_part = 9 - (ScientificNotation.Length + 1 + 2);
//小数位由此算出
NumberProcess = new BigNumber(Number.ToString()) / (new BigNumber("10")).Power(new BigNumber(ScientificNumber.ToString()), 30);
ProcessedNumber = MathV.round(NumberProcess.ToString(), digits_part, 0) + "E+" + ScientificNotation;
}
else
{
//如果已经大于已经大于九位了，则不作处理
//这种情况极为罕见，不考虑
NumberProcess = new BigNumber(Number.ToString()) / (new BigNumber("10")).Power(new BigNumber(ScientificNumber.ToString()), 30);
ProcessedNumber = MathV.round(NumberProcess.ToString(), 0, 0) + "E+" + ScientificNotation;
}
}
else
{
ProcessedNumber = MathV.round(Number, 4, 0);
}
}
else
{
zero_count = 0;
foreach (char EachDigit in NumberParts[1])
{
if (EachDigit == '0')
{
zero_count++;
}
else
{
break;
}
}
ScientificNumber = zero_count + 1;
//科学计数法的数字为零的个数加1
if (ScientificNumber <= 9 && ScientificNumber > 0)
{
ScientificNotation = "0" + ScientificNumber.ToString();
//如果科学计数法为个位要补零
}
else
{
ScientificNotation = ScientificNumber.ToString();
}
if (ScientificNotation.Length + 1 + 2 <= 9)
{
//例如：-2.654E-05
//数字负号占一位，E和科学计数法的符号占两位
//大于9的情况不做考虑，数字太大。
digits_part = 9 - (ScientificNotation.Length + 1 + 2);
//小数位由此算出
NumberProcess = new BigNumber(Number.ToString()) * (new BigNumber("10")).Power(new BigNumber(ScientificNumber.ToString()), 30);
ProcessedNumber = MathV.round(NumberProcess.ToString(), digits_part, 0) + "E-" + ScientificNotation;
}
else
{
//如果已经大于已经大于九位了，则不作处理
//这种情况极为罕见，不考虑
NumberProcess = new BigNumber(Number.ToString()) * (new BigNumber("10")).Power(new BigNumber(ScientificNumber.ToString()), 30);
ProcessedNumber = MathV.round(NumberProcess.ToString(), 0, 0) + "E-" + ScientificNotation;
}
}
}
}
else {
ProcessedNumber = MathV.round(Number,4,0);
//如果本身长度就在十个单位以内，则不作处理
//保留四位小数
}
if (ProcessedNumber.Length < 11)
{
ProcessedNumber = ProcessedNumber.PadLeft(11, ' ');
//11个单位的长度是为了预留量
}
Console.WriteLine("ProcessedNumber={0}", ProcessedNumber);
Console.ReadKey();
}
}
}