1507.ReformatDate(String).py

"""
    Given a date string in the form Day Month Year, where:
        - Day is in the set {"1st", "2nd", "3rd", "4th", ..., "30th", "31st"}.
        - Month is in the set {"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", 
                               "Aug", "Sep", "Oct", "Nov", "Dec"}.
        - Year is in the range [1900, 2100].

    Convert the date string to the format YYYY-MM-DD, where:
        - YYYY denotes the 4 digit year.
        - MM denotes the 2 digit month.
        - DD denotes the 2 digit day.

    Example:
    Input: date = "20th Oct 2052"
    Output: "2052-10-20"

    Constraints:
        - The given dates are guaranteed to be valid, so no error handling is n
          ecessary.
"""
#Difficulty: Easy
#110 / 110 test cases passed.
#Runtime: 40 ms
#Memory Usage: 13.8 MB

#Runtime: 40 ms, faster than 100.00% of Python3 online submissions for Reformat Date.
#Memory Usage: 13.8 MB, less than 100.00% of Python3 online submissions for Reformat Date.    

class Solution:
    def reformatDate(self, date: str) -> str:
        months = {"Jan":"01", "Feb":"02", "Mar":"03", "Apr":"04", "May":"05", 
                  "Jun":"06", "Jul":"07", "Aug":"08", "Sep":"09", "Oct":"10", 
                  "Nov":"11", "Dec":"12"}
        if date[1].isalpha(): date = "0" + date
        return date[-4:] + '-' + months[date[5:8]] + '-' + date[:2]