README_EN.md

comments	difficulty	edit_url	tags
true	Easy	https://github.com/doocs/leetcode/edit/main/solution/0100-0199/0196.Delete%20Duplicate%20Emails/README_EN.md	Database

196. Delete Duplicate Emails

中文文档

Description

Table: Person

+-------------+---------+
| Column Name | Type    |
+-------------+---------+
| id          | int     |
| email       | varchar |
+-------------+---------+
id is the primary key (column with unique values) for this table.
Each row of this table contains an email. The emails will not contain uppercase letters.

 

Write a solution to delete all duplicate emails, keeping only one unique email with the smallest id.

For SQL users, please note that you are supposed to write a DELETE statement and not a SELECT one.

For Pandas users, please note that you are supposed to modify Person in place.

After running your script, the answer shown is the Person table. The driver will first compile and run your piece of code and then show the Person table. The final order of the Person table does not matter.

The result format is in the following example.

 

Example 1:

Input: 
Person table:
+----+------------------+
| id | email            |
+----+------------------+
| 1  | john@example.com |
| 2  | bob@example.com  |
| 3  | john@example.com |
+----+------------------+
Output: 
+----+------------------+
| id | email            |
+----+------------------+
| 1  | john@example.com |
| 2  | bob@example.com  |
+----+------------------+
Explanation: john@example.com is repeated two times. We keep the row with the smallest Id = 1.

Solutions

Solution 1

Python3

import pandas as pd


# Modify Person in place
def delete_duplicate_emails(person: pd.DataFrame) -> None:
    # Sort the rows based on id (Ascending order)
    person.sort_values(by="id", ascending=True, inplace=True)
    # Drop the duplicates based on email.
    person.drop_duplicates(subset="email", keep="first", inplace=True)

MySQL

# Write your MySQL query statement below
DELETE FROM Person
WHERE id NOT IN (SELECT MIN(id) FROM (SELECT * FROM Person) AS p GROUP BY email);

Solution 2

MySQL

# Write your MySQL query statement below
DELETE FROM Person
WHERE
    id NOT IN (
        SELECT id
        FROM
            (
                SELECT
                    id,
                    ROW_NUMBER() OVER (
                        PARTITION BY email
                        ORDER BY id
                    ) AS rk
                FROM Person
            ) AS p
        WHERE rk = 1
    );

Solution 3

MySQL

DELETE p2
FROM
    person AS p1
    JOIN person AS p2 ON p1.email = p2.email
WHERE
    p1.id < p2.id;