Skip to content

Latest commit

 

History

History
266 lines (215 loc) · 8.1 KB

README_EN.md

File metadata and controls

266 lines (215 loc) · 8.1 KB
comments difficulty edit_url rating source tags
true
Hard
1853
Biweekly Contest 16 Q4
Array
Dynamic Programming
Matrix

1301. Number of Paths with Max Score

中文文档

Description

You are given a square board of characters. You can move on the board starting at the bottom right square marked with the character 'S'.

You need to reach the top left square marked with the character 'E'. The rest of the squares are labeled either with a numeric character 1, 2, ..., 9 or with an obstacle 'X'. In one move you can go up, left or up-left (diagonally) only if there is no obstacle there.

Return a list of two integers: the first integer is the maximum sum of numeric characters you can collect, and the second is the number of such paths that you can take to get that maximum sum, taken modulo 10^9 + 7.

In case there is no path, return [0, 0].

 

Example 1:

Input: board = ["E23","2X2","12S"]

Output: [7,1]

Example 2:

Input: board = ["E12","1X1","21S"]

Output: [4,2]

Example 3:

Input: board = ["E11","XXX","11S"]

Output: [0,0]

 

Constraints:

    <li><code>2 &lt;= board.length == board[i].length &lt;= 100</code></li>

Solutions

Solution 1: Dynamic Programming

We define $f[i][j]$ to represent the maximum score from the starting point $(n - 1, n - 1)$ to $(i, j)$, and $g[i][j]$ to represent the number of ways to achieve the maximum score from the starting point $(n - 1, n - 1)$ to $(i, j)$. Initially, $f[n - 1][n - 1] = 0$ and $g[n - 1][n - 1] = 1$. The other positions of $f[i][j]$ are all $-1$, and $g[i][j]$ are all $0$.

For the current position $(i, j)$, it can be transferred from three positions: $(i + 1, j)$, $(i, j + 1)$, and $(i + 1, j + 1)$. Therefore, we can enumerate these three positions to update the values of $f[i][j]$ and $g[i][j]$. If the current position $(i, j)$ has an obstacle, or the current position is the starting point, or other positions are out of bounds, no update is performed. Otherwise, if another position $(x, y)$ satisfies $f[x][y] \gt f[i][j]$, then we update $f[i][j] = f[x][y]$ and $g[i][j] = g[x][y]$. If $f[x][y] = f[i][j]$, then we update $g[i][j] = g[i][j] + g[x][y]$. Finally, if the current position $(i, j)$ is reachable and is a number, we update $f[i][j] = f[i][j] + board[i][j]$.

Finally, if $f[0][0] \lt 0$, it means there is no path to reach the endpoint, return $[0, 0]$. Otherwise, return $[f[0][0], g[0][0]]$. Note that the result needs to be taken modulo $10^9 + 7$.

Time complexity $O(n^2)$, space complexity $O(n^2)$. Where $n$ is the side length of the array.

Python3

class Solution:
    def pathsWithMaxScore(self, board: List[str]) -> List[int]:
        def update(i, j, x, y):
            if x >= n or y >= n or f[x][y] == -1 or board[i][j] in "XS":
                return
            if f[x][y] > f[i][j]:
                f[i][j] = f[x][y]
                g[i][j] = g[x][y]
            elif f[x][y] == f[i][j]:
                g[i][j] += g[x][y]

        n = len(board)
        f = [[-1] * n for _ in range(n)]
        g = [[0] * n for _ in range(n)]
        f[-1][-1], g[-1][-1] = 0, 1
        for i in range(n - 1, -1, -1):
            for j in range(n - 1, -1, -1):
                update(i, j, i + 1, j)
                update(i, j, i, j + 1)
                update(i, j, i + 1, j + 1)
                if f[i][j] != -1 and board[i][j].isdigit():
                    f[i][j] += int(board[i][j])
        mod = 10**9 + 7
        return [0, 0] if f[0][0] == -1 else [f[0][0], g[0][0] % mod]

Java

class Solution {
    private List<String> board;
    private int n;
    private int[][] f;
    private int[][] g;
    private final int mod = (int) 1e9 + 7;

    public int[] pathsWithMaxScore(List<String> board) {
        n = board.size();
        this.board = board;
        f = new int[n][n];
        g = new int[n][n];
        for (var e : f) {
            Arrays.fill(e, -1);
        }
        f[n - 1][n - 1] = 0;
        g[n - 1][n - 1] = 1;
        for (int i = n - 1; i >= 0; --i) {
            for (int j = n - 1; j >= 0; --j) {
                update(i, j, i + 1, j);
                update(i, j, i, j + 1);
                update(i, j, i + 1, j + 1);
                if (f[i][j] != -1) {
                    char c = board.get(i).charAt(j);
                    if (c >= '0' && c <= '9') {
                        f[i][j] += (c - '0');
                    }
                }
            }
        }
        int[] ans = new int[2];
        if (f[0][0] != -1) {
            ans[0] = f[0][0];
            ans[1] = g[0][0];
        }
        return ans;
    }

    private void update(int i, int j, int x, int y) {
        if (x >= n || y >= n || f[x][y] == -1 || board.get(i).charAt(j) == 'X'
            || board.get(i).charAt(j) == 'S') {
            return;
        }
        if (f[x][y] > f[i][j]) {
            f[i][j] = f[x][y];
            g[i][j] = g[x][y];
        } else if (f[x][y] == f[i][j]) {
            g[i][j] = (g[i][j] + g[x][y]) % mod;
        }
    }
}

C++

class Solution {
public:
    vector<int> pathsWithMaxScore(vector<string>& board) {
        int n = board.size();
        const int mod = 1e9 + 7;
        int f[n][n];
        int g[n][n];
        memset(f, -1, sizeof(f));
        memset(g, 0, sizeof(g));
        f[n - 1][n - 1] = 0;
        g[n - 1][n - 1] = 1;

        auto update = [&](int i, int j, int x, int y) {
            if (x >= n || y >= n || f[x][y] == -1 || board[i][j] == 'X' || board[i][j] == 'S') {
                return;
            }
            if (f[x][y] > f[i][j]) {
                f[i][j] = f[x][y];
                g[i][j] = g[x][y];
            } else if (f[x][y] == f[i][j]) {
                g[i][j] = (g[i][j] + g[x][y]) % mod;
            }
        };

        for (int i = n - 1; i >= 0; --i) {
            for (int j = n - 1; j >= 0; --j) {
                update(i, j, i + 1, j);
                update(i, j, i, j + 1);
                update(i, j, i + 1, j + 1);
                if (f[i][j] != -1) {
                    if (board[i][j] >= '0' && board[i][j] <= '9') {
                        f[i][j] += (board[i][j] - '0');
                    }
                }
            }
        }
        vector<int> ans(2);
        if (f[0][0] != -1) {
            ans[0] = f[0][0];
            ans[1] = g[0][0];
        }
        return ans;
    }
};

Go

func pathsWithMaxScore(board []string) []int {
	n := len(board)
	f := make([][]int, n)
	g := make([][]int, n)
	for i := range f {
		f[i] = make([]int, n)
		g[i] = make([]int, n)
		for j := range f[i] {
			f[i][j] = -1
		}
	}
	f[n-1][n-1] = 0
	g[n-1][n-1] = 1
	const mod = 1e9 + 7

	update := func(i, j, x, y int) {
		if x >= n || y >= n || f[x][y] == -1 || board[i][j] == 'X' || board[i][j] == 'S' {
			return
		}
		if f[x][y] > f[i][j] {
			f[i][j] = f[x][y]
			g[i][j] = g[x][y]
		} else if f[x][y] == f[i][j] {
			g[i][j] = (g[i][j] + g[x][y]) % mod
		}
	}
	for i := n - 1; i >= 0; i-- {
		for j := n - 1; j >= 0; j-- {
			update(i, j, i+1, j)
			update(i, j, i, j+1)
			update(i, j, i+1, j+1)
			if f[i][j] != -1 && board[i][j] >= '0' && board[i][j] <= '9' {
				f[i][j] += int(board[i][j] - '0')
			}
		}
	}
	ans := make([]int, 2)
	if f[0][0] != -1 {
		ans[0], ans[1] = f[0][0], g[0][0]
	}
	return ans
}