Concatenate lists in a column?

[seolmor]

Given a column with three rows, each row holding a list, is it possible to concatenate the lists?

q1[n] <- [[["apple","pear"]],[["plum"]],[["pear"]]] 
?[collect(y)] := q1[n], y=concat(n)

With or without the y=concat(n) clause, the above outputs -

[["apple", "pear"], ["pear"], ["plum"]]

I'm trying to get -

["apple", "pear", "pear", "plum"]

[matthiasautrata]

maybe union(...) instead of concat? (set union, not bag, like you asked?)

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On Thu, Jul 13, 2023 at 7:56 AM seolmor ***@***.***> wrote: Given a column with three rows, each row holding a list, is it possible to concatenate the lists? q1[n] <- [[["apple","pear"]],[["plum"]],[["pear"]]] ?[collect(y)] := q1[n], y=concat(n) With or without the y=concat(n) clause, the above outputs - [["apple", "pear"], ["pear"], ["plum"]] I'm trying to get - ["apple", "pear", "pear", "plum"] — Reply to this email directly, view it on GitHub <#147>, or unsubscribe <https://github.com/notifications/unsubscribe-auth/AL52JJQXNVHDSJLIKYQXTRLXP7O7BANCNFSM6AAAAAA2I2SCSU> . You are receiving this because you are subscribed to this thread.Message ID: ***@***.***>

[seolmor]

Thank you.

union(...) produces a set but I want a bag to retain the second occurrence of "pear"

q1[n] <- [[["apple","pear"]],[["plum"]],[["pear"]]] 
?[union(n)] := q1[n]
=>
 union(n) 
---------------------------
 ["apple", "pear", "plum"]