ex2.56-add-exponent-to-deriv.scm

(define (deriv exp var)
  (cond ((number? exp) 0)
	((variable? exp)
	 (if (same-variable? exp var) 1 0))
	((sum? exp)
	 (write-line "deconstruct sum")
	 (make-sum (deriv (addend exp) var)
		   (deriv (augend exp) var)))
	((product? exp)
	 (write-line "deconstruct product")
	 (make-sum
	   (make-product (multiplier exp)
			 (deriv (multiplicand exp) var))
	   (make-product (deriv (multiplier exp) var)
			 (multiplicand exp))))
	((exponentiation? exp)
	 (write-line "deconstruct exponentiation")
	 (make-product
	   (make-product (exponent exp)
			 (make-exponentiation (base exp) (- (exponent exp) 1))) ;; this is wrong!!! since (exponent exp) not necessarily to be a number, should reuse make-sum!
	   (deriv (base exp) var)))
	(else
	  (error "unknown expression type -- DERIV" exp))))


(define (variable? x) (symbol? x))
(define (same-variable? v1 v2) (and (variable? v1) (variable? v2) (eq? v1 v2)))
(define (=number? exp num) (and (number? exp) (= exp num)))
(define (make-sum a1 a2)
  (cond ((=number? a1 0) a2)
	((=number? a2 0) a1)
	((and (number? a1) (number? a2)) (+ a1 a2))
	(else (list '+ a1 a2))))

(define (make-product m1 m2)
  (cond ((or (=number? m1 0) (=number? m2 0)) 0)
	((=number? m1 1) m2)
	((=number? m2 1) m1)
	((and (number? m1) (number? m2)) (* m1 m2))
	(else (list '* m1 m2))))

(define (make-exponentiation base exponent)
  (cond ((=number? exponent 0) 1)
	((=number? exponent 1) base)  ;; ((=number? base 1) 1) 
	(else (list '** base exponent))))

(define (exponentiation? x) (and (pair? x) (eq? (car x) '**)))
(define base cadr)
(define exponent caddr)

(define (sum? x) (and (pair? x) (eq? (car x) '+)))
(define (addend s) (cadr s))
(define (augend s) (caddr s))
(define (product? x) (and (pair? x) (eq? (car x) '*)))
(define (multiplier p) (cadr p))
(define (multiplicand p) (caddr p))


(deriv '(* (*x x 4) (+ x 3)) 'x)
(deriv '(** x 4) 'x)