You are given a 2D integer array logs
where each logs[i] = [birthi, deathi]
indicates the birth and death years of the ith
person.
The population of some year x
is the number of people alive during that year. The ith
person is counted in year x
's population if x
is in the inclusive range [birthi, deathi - 1]
. Note that the person is not counted in the year that they die.
Return the earliest year with the maximum population.
Input: logs = [[1993,1999],[2000,2010]] Output: 1993 Explanation: The maximum population is 1, and 1993 is the earliest year with this population.
Input: logs = [[1950,1961],[1960,1971],[1970,1981]] Output: 1960 Explanation: The maximum population is 2, and it had happened in years 1960 and 1970. The earlier year between them is 1960.
1 <= logs.length <= 100
1950 <= birthi < deathi <= 2050
impl Solution {
pub fn maximum_population(logs: Vec<Vec<i32>>) -> i32 {
let mut max = 0;
let mut ret = 1950;
for year in 1950..=2050 {
let population = logs
.iter()
.filter(|&log| (log[0]..log[1]).contains(&year))
.count();
if population > max {
max = population;
ret = year;
}
}
ret
}
}