Given an integer num
, return the number of digits in num
that divide num
.
An integer val
divides nums
if nums % val == 0
.
Input: num = 7 Output: 1 Explanation: 7 divides itself, hence the answer is 1.
Input: num = 121 Output: 2 Explanation: 121 is divisible by 1, but not 2. Since 1 occurs twice as a digit, we return 2.
Input: num = 1248 Output: 4 Explanation: 1248 is divisible by all of its digits, hence the answer is 4.
1 <= num <= 109
num
does not contain0
as one of its digits.
impl Solution {
pub fn count_digits(num: i32) -> i32 {
let mut x = num;
let mut ret = 0;
while x > 0 {
if num % (x % 10) == 0 {
ret += 1;
}
x /= 10;
}
ret
}
}