README.md

2540. Minimum Common Value

Given two integer arrays nums1 and nums2, sorted in non-decreasing order, return the minimum integer common to both arrays. If there is no common integer amongst nums1 and nums2, return -1.

Note that an integer is said to be common to nums1 and nums2 if both arrays have at least one occurrence of that integer.

Example 1:

Input: nums1 = [1,2,3], nums2 = [2,4]
Output: 2
Explanation: The smallest element common to both arrays is 2, so we return 2.

Example 2:

Input: nums1 = [1,2,3,6], nums2 = [2,3,4,5]
Output: 2
Explanation: There are two common elements in the array 2 and 3 out of which 2 is the smallest, so 2 is returned.

Constraints:

• 1 <= nums1.length, nums2.length <= 105
• 1 <= nums1[i], nums2[j] <= 109
• Both nums1 and nums2 are sorted in non-decreasing order.

Solutions (Rust)

1. Solution

impl Solution {
    pub fn get_common(nums1: Vec<i32>, nums2: Vec<i32>) -> i32 {
        let mut i = 0;
        let mut j = 0;

        while i < nums1.len() && j < nums2.len() {
            if nums1[i] == nums2[j] {
                return nums1[i];
            } else if nums1[i] < nums2[j] {
                i += 1;
            } else {
                j += 1;
            }
        }

        -1
    }
}