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LargestPlusSign.java
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// @author Santhosh
class Solution {
public int orderOfLargestPlusSign(int n, int[][] mines) {
int[][] grid = new int[n][n];
for (int[] row : grid) {
Arrays.fill(row, 1);
}
for (int[] mine : mines) {
grid[mine[0]][mine[1]] = 0;
}
int[][] dp = new int[n][n];
for (int[] row : dp) {
Arrays.fill(row, n);
}
int curSum;
for (int i = 0; i < n; i++) {
curSum = 0;
for (int j = 0; j < n; j++) {
if (grid[i][j] == 0)
curSum = 0;
else
curSum++;
dp[i][j] = Math.min(dp[i][j], curSum);
}
curSum = 0;
for (int j = n - 1; j >= 0; j--) {
if (grid[i][j] == 0)
curSum = 0;
else
curSum++;
dp[i][j] = Math.min(dp[i][j], curSum);
}
}
for (int j = 0; j < n; j++) {
curSum = 0;
for (int i = 0; i < n; i++) {
if (grid[i][j] == 0)
curSum = 0;
else
curSum++;
dp[i][j] = Math.min(dp[i][j], curSum);
}
curSum = 0;
for (int i = n - 1; i >= 0; i--) {
if (grid[i][j] == 0)
curSum = 0;
else
curSum++;
dp[i][j] = Math.min(dp[i][j], curSum);
}
}
int ans = 0;
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
ans = Math.max(ans, dp[i][j]);
}
}
return ans;
}
}
//@Sunchit
class Solution {
public int orderOfLargestPlusSign(int n, int[][] mines) {
int[][] inputGrid = new int[n][n];
for(int[] row: inputGrid){
Arrays.fill(row, 1);
}
for(int[] mine : mines){
inputGrid[mine[0]][mine[1]] =0;
}
int[][] lTR = new int[n][n];
for(int i=0;i<n;i++){
int runningSum = 0;
for(int j=0;j<n;j++){
if(inputGrid[i][j] == 0){
runningSum = 0;
} else {
runningSum = inputGrid[i][j]+runningSum;
}
lTR[i][j] = runningSum;
}
}
int[][] rTL = new int[n][n];
for(int i=0;i<n;i++){
int runningSum = 0;
for(int j=n-1;j>=0;j--){
if(inputGrid[i][j] == 0){
runningSum = 0;
} else {
runningSum = inputGrid[i][j]+runningSum;
}
rTL[i][j] = runningSum;
}
}
int[][] tTB = new int[n][n];
for(int i=0;i<n;i++){
int runningSum = 0;
for(int j=0;j<n;j++){
if(inputGrid[j][i] == 0){
runningSum = 0;
} else {
runningSum = inputGrid[j][i]+runningSum;
}
tTB[j][i] = runningSum;
}
}
int[][] bTT = new int[n][n];
for(int i=0;i<n;i++){
int runningSum = 0;
for(int j=n-1;j>=0;j--){
if(inputGrid[j][i] == 0){
runningSum = 0;
} else {
runningSum = inputGrid[j][i]+runningSum;
}
bTT[j][i] = runningSum;
}
}
int ans=0;
for(int i=0;i<n;i++){
for(int j=0;j<n;j++){
int minLen = Math.min(Math.min(lTR[i][j], rTL[i][j]) , Math.min(bTT[i][j], tTB[i][j]));
ans = Math.max(ans, minLen);
}
}
return ans;
}
}