718. Maximum Length of Repeated Subarray

// 718. Maximum Length of Repeated Subarray
// 66 ms	48.2 MB
class Solution {
    public int findLength(int[] nums1, int[] nums2) {
        
        int[][] dp=new int[nums1.length+1][nums2.length+1];
        int longest=0;
        
        for(int i=1;i<dp.length;i++)
            for(int j=1;j<dp[0].length;j++)
               if(nums1[i-1]==nums2[j-1]){
                   dp[i][j]=dp[i-1][j-1]+1;
                longest=Math.max(dp[i][j],longest);
               }
        return longest;
        
    }
}