How to set FileName when creating Files?

[jlewi]

Is it possible to set the filename when uploading a file?

File.New takes a FileNewParams
https://github.com/openai/openai-[go/blob/23d40fd68d5a6683066552ee39bfee2fdd35429d/file.go#L64](https://www.golinks.io/blob/23d40fd68d5a6683066552ee39bfee2fdd35429d/file.go#L64?trackSource=github)
and FileNewParams seems to be missing the FileName field
https://github.com/openai/openai-[go/blob/23d40fd68d5a6683066552ee39bfee2fdd35429d/file.go#L313](https://www.golinks.io/blob/23d40fd68d5a6683066552ee39bfee2fdd35429d/file.go#L313?trackSource=github)

[jacobzim-stl]

I believe #91 should help

(Edited to fix link)

[ThadeuMelo]

I believe [https://github.com/openai/openai-go/issues/91#issuecomment-2451824003](https://github.com/openai/openai-%5Bgo/issues/91#issuecomment-2451824003%5D(https://www.golinks.io/issues/91#issuecomment-2451824003?trackSource=github)) should help

I can't open these links.

Also I think this might be the reason my my current issue:

"{\n \"error\": {\n \"message\": \"Files with extensions [none] are not supported for retrieval. See https://platform.openai.com/docs/assistants/tools/file-search/supported-files\",\n \"type\": \"invalid_request_error\",\n \"param\": \"file_ids\",\n \"code\": \"unsupported_file\"\n }\n}"

I'm uploading .txt files that should be supported.

[jacobzim-stl]

Sorry about that bad link, does the solution in #91 work?

[vkuptcov]

@jlewi @jacobzim-stl there is openai.FileParam parameter that might be used in such a case:

openai-go/field.go

Line 39 in 952d231

func FileParam(reader io.Reader, filename string, contentType string) param.Field[io.Reader] {

// FileParam is a param field helper which helps files with a mime content-type.
func FileParam(reader io.Reader, filename string, contentType string) param.Field[io.Reader] {
	return F[io.Reader](&file{reader, filename, contentType})
}

type file struct {
	io.Reader
	name        string
	contentType string
}

func (f *file) Name() string        { return f.name }
func (f *file) ContentType() string { return f.contentType }