Group Anagrams leetcode-49

class Solution(object):
    def groupAnagrams(self, li):
        dictionary = {}
        for word in li:
           sortedWord = ''.join(sorted(word))
           # If word is not in dictionary
           if sortedWord not in dictionary:
               dictionary[sortedWord] = [word]
           # If previously it is present that means its anagram
           # was previously present
           else:
               dictionary[sortedWord] += [word]
        return [dictionary[i] for i in dictionary]