1092. To Buy or Not to Buy.cpp

#include <bits/stdc++.h>
using namespace std;
using gg = long long;
int main() {
    ios::sync_with_stdio(false);
    cin.tie(0);
    string s1, s2;
    getline(cin, s1);
    getline(cin, s2);
    array<gg, 128> h{};
    for (char c : s1)
        ++h[c];
    for (char c : s2)
        --h[c];
    gg k1 = 0, k2 = 0;  // k1记录多余的珠子数，k2记录少的珠子数
    for (int i : h) {
        i > 0 ? k1 += i : k2 -= i;
    }
    k2 > 0 ? cout << "No " << k2 : cout << "Yes " << k1;
    return 0;
}