We read every piece of feedback, and take your input very seriously.
To see all available qualifiers, see our documentation.
Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.
By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.
Already on GitHub? Sign in to your account
如题,想做一个通用的 SearchBean,可以查询任意表的任意字段,不用每张表都要定义一个 @SearchBean VO!
由于 BeanSearcher 和 MapSearcher 的搜索方法只支持 Class<?> beanClass,没有提供 BeanMeta 的入参及它的 Builder 方法,是否有其它方式能实现这种需求?
The text was updated successfully, but these errors were encountered:
建一个BaseController<BaseService,BaseEntity>,传入BaseEntity.class就可以了呀。
Sorry, something went wrong.
可以把 SearchBean 定义信息配置到数据库,然后从数据库加载后再动态生成 beanClass 对象,这样就动态了。
No branches or pull requests
如题,想做一个通用的 SearchBean,可以查询任意表的任意字段,不用每张表都要定义一个 @SearchBean VO!
由于 BeanSearcher 和 MapSearcher 的搜索方法只支持 Class<?> beanClass,没有提供 BeanMeta 的入参及它的 Builder 方法,是否有其它方式能实现这种需求?
The text was updated successfully, but these errors were encountered: