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Copy path103_BinaryTreeZigzagLevelOrderTraversal.java
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103_BinaryTreeZigzagLevelOrderTraversal.java
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/*
* Given a binary tree, return the zigzag level order traversal of its nodes'
* values.
* (ie, from left to right, then right to left for the next level and alternate
* between).
* For example:
* Given binary tree {3,9,20,#,#,15,7},
* 3
* / \
* 9 20
* / \
* 15 7
* return its zigzag level order traversal as:
* [
* [3],
* [20,9],
* [15,7]
* ]
*/
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
//two stack
public class Solution {
public List<List<Integer>> zigzagLevelOrder(TreeNode root) {
Stack<TreeNode> curL = new Stack<>();
Stack<TreeNode> nextL = new Stack<>();
Stack<TreeNode> temp;
List<List<Integer>> res new ArrayList<List<Integer>>();
if(root == null) return res;
curL.push(root);
boolean normal = true;
while(!curL.isEmpty()) {
List<Integer> list = new ArrayList<>();
while(!curL.isEmpty()) {
TreeNode node = curL.pop();
list.add(curL.val);
if(normal) {
if(node.left != null) nextL.push(node.left);
if(node.right != null) nextL.push(node.right);
}else {
if(node.right != null) nextL.push(node.right);
if(node.left != null) nextL.push(node.left);
}
}
res.add(list);
temp = curL;
curL = nextL;
nextL = temp;
normal = !normal;
}
return res;
}
}
//这叫啥方法
public class Solution {
public List<List<Integer>> zigzagLevelOrder(TreeNode root) {
List<List<Integer>> res = new ArrayList<List<Integer>>();
List<Integer> list = new ArrayList<>();
helper(root, res, 0);
return res;
}
private void helper(TreeNode root, List<List<Integer>> res, int level) {
if(root == null) return;
if(res.size() <= level) {
List<Integer> temp = new ArrayList<>();
res.add(temp);
}
List<Integer> list = res.get(level);
if(level % 2 == 1) {
list.add(0, root.val);
} else {
list.add(root.val);
}
helper(root.left, res, level + 1);
helper(root.right, res, level + 1);
}
}