add task solution #3795
add task solution #3795
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Your implementation of the convertToObject function is well done and meets the task requirements! 🎉 You've effectively used iteration methods like map and filter to transform the input string into a style object, and your approach aligns with the constraints provided. Keep up the great work, and continue honing your skills with these techniques! 😊
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| @@ -6,7 +6,21 @@ | |||
| * @return {object} | |||
| */ | |||
| function convertToObject(sourceString) { | |||
| // write your code here | |||
| const filteredArray = sourceString | |||
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The initial split operation on the sourceString is correct, as it divides the string into an array of style declarations based on semicolons.
| const styleObject = {}; | ||
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| for (const element of filteredArray) { | ||
| const [property, value] = element.split(':').map((part) => part.trim()); |
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The split operation on element by colon is correct for separating property and value. However, note that handling multiple colons within a value is not required according to the additional prompt instructions.
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