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3001-3100/3043. Find the Length of the Longest Common Prefix.md
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# 3043. Find the Length of the Longest Common Prefix | ||
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- Difficulty: Medium. | ||
- Related Topics: Array, Hash Table, String, Trie. | ||
- Similar Questions: Longest Common Prefix, Longest Common Suffix Queries. | ||
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## Problem | ||
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You are given two arrays with **positive** integers `arr1` and `arr2`. | ||
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A **prefix** of a positive integer is an integer formed by one or more of its digits, starting from its **leftmost** digit. For example, `123` is a prefix of the integer `12345`, while `234` is **not**. | ||
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A **common prefix** of two integers `a` and `b` is an integer `c`, such that `c` is a prefix of both `a` and `b`. For example, `5655359` and `56554` have a common prefix `565` while `1223` and `43456` **do not** have a common prefix. | ||
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You need to find the length of the **longest common prefix** between all pairs of integers `(x, y)` such that `x` belongs to `arr1` and `y` belongs to `arr2`. | ||
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Return **the length of the **longest** common prefix among all pairs**.** If no common prefix exists among them**, **return** `0`. | ||
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Example 1: | ||
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``` | ||
Input: arr1 = [1,10,100], arr2 = [1000] | ||
Output: 3 | ||
Explanation: There are 3 pairs (arr1[i], arr2[j]): | ||
- The longest common prefix of (1, 1000) is 1. | ||
- The longest common prefix of (10, 1000) is 10. | ||
- The longest common prefix of (100, 1000) is 100. | ||
The longest common prefix is 100 with a length of 3. | ||
``` | ||
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Example 2: | ||
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``` | ||
Input: arr1 = [1,2,3], arr2 = [4,4,4] | ||
Output: 0 | ||
Explanation: There exists no common prefix for any pair (arr1[i], arr2[j]), hence we return 0. | ||
Note that common prefixes between elements of the same array do not count. | ||
``` | ||
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**Constraints:** | ||
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- `1 <= arr1.length, arr2.length <= 5 * 104` | ||
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- `1 <= arr1[i], arr2[i] <= 108` | ||
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## Solution | ||
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```javascript | ||
/** | ||
* @param {number[]} arr1 | ||
* @param {number[]} arr2 | ||
* @return {number} | ||
*/ | ||
var longestCommonPrefix = function(arr1, arr2) { | ||
var trie = {}; | ||
for (var i = 0; i < arr1.length; i++) { | ||
var str = `${arr1[i]}`; | ||
var map = trie; | ||
for (var j = 0; j < str.length; j++) { | ||
if (!map[str[j]]) { | ||
map[str[j]] = {}; | ||
} | ||
map = map[str[j]]; | ||
} | ||
} | ||
var max = 0; | ||
for (var i = 0; i < arr2.length; i++) { | ||
var str = `${arr2[i]}`; | ||
var map = trie; | ||
var len = 0; | ||
for (var j = 0; j < str.length; j++) { | ||
if (!map[str[j]]) { | ||
break; | ||
} | ||
len += 1; | ||
map = map[str[j]]; | ||
} | ||
max = Math.max(max, len); | ||
} | ||
return max; | ||
}; | ||
``` | ||
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**Explain:** | ||
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Trie. | ||
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**Complexity:** | ||
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* Time complexity : O(n * m). | ||
* Space complexity : O(n * m). |